Question

no. of molecules in 150 g CaCO3
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Answer 1

Answer:

No. of moles = given mass of compound / Molar mass

Given mass = 10g

Molar mass = (40 + 12 + 3x16) =100g/mol

No of moles of CaCO3 = 10 / 100 =0.1 mol

According to Avogadro’s law –

1 mol of CaCO3 molecules contains 6.022 x 1023 CaCO3 molecules

Hence, 0.1 mol of CaCO3 molecules will contain 6.022 x 1023x 0.1 molecules

i.e. 0.6022 x 1023 or 6.022 x 1022 molecules