no.of molecules in 1g of cl2
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Explanation:
The approach is outlined below: 39.2 g Cl2(1 mole of Cl270.9 g Cl2)(6.022⋅1023molecules Cl21 mole Cl2)=3.33⋅1023 molecules Cl2 . Hence, the answer is 3.33⋅1023 molecules of Cl2
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