Question

No of molecules in 50g of CACO3. Calculate the no of moles present in 3.011* 10^23

Answer 1

First calculate the atomic mass of calcium carbonate.
$ca + c + 3c \\ = 40 + 12 + 48 \\ = 100g$
Now we know that one mole calcium carbonate is of 100 grams. Thus 50 grams will be half a mole.

Now
$1 \: mole = 6.022 \times {10}^{23} \\ 3.011 \times {10}^{23} = \frac{1}{6.022 \times {10}^{23} } \times 3.011 \times {10}^{23} moles \\ = \frac{1}{2} moles$
Mark it as the brainliest answer if this helps.

Answer 2

Formula mass of caco3=40+12+3-100amu..

100g Caco3=1mole.. , 50g of caco3=1÷100×50=0.5 mol..