no.of molecules in a 19.6 gm of H2SO4
Answers
molar mass of H2SO4 is 98 unit
98 gm of H2SO4 contains 6.022 × 10 ^23
so that in 19.6 gm of H2SO4 x much molecules obtained.
x = 6.022 × 10 ^23 × 19.6 / 98
x = 1.2044 × 10^23 molecules
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Primary SchoolChemistry 5+3 pts
How many molecules of H2SO4 are there in a 49g sample?
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Prashantkanchkatle78 · Helping Hand
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Rajusingh45
Rajusingh45
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Let's write the given:
Mass of Sulphuric (H2SO4) = 49g
We have the number of molecules in 49g of H2SO4
explanation=)
Molecular mass of H2SO4 = (Atomic mass of H) x 2 + (Atomic mass of S) x 1 + (Atomic mass of O) x 4
Molecular mass of H2SO4 = ( 1 x 2) + (32 x 1) + (16 x 4)
= 2 + 32 + 64
= 98.
Now,
According to the formula,
Number of moles in the given H2SO4(n)
= Mass of H2SO4 in grams/Molecular mass of H2SO4
= 49/98
= 1/2
= 0.5
: n = 0.5 mol
: 1 mol of H2SO4 contains 6.022 x 10^23 molecules.
: 0.5 mol of H2SO4 contains 0.5 x 6.022 x 10^23 molecules.
= 3.011 x 10^23 molecules .
that is 49 g of H2SO4 contains 3.011 x 10^23 molecules of H2SO4.