Question

No. of molecules of hcl=1.2×10²⁴/m³ .find normality

Answer 1

I mole = 6.023 x 10^23 molecules

=> 1 molecule = 1/ 6.023 x 10^23 moles

=> 1.2 x 10^24 molecules =

(1/6.023 x 10^23 ) x 1.2 x 10^24

= 1.99 moles

= 2 moles (approx).

Nomality = number of gram equivalent / volume of soln. in litres

= 2 * 36.5/ 36.5

—-————————

1000 ( 1 m^3 = 1000 lit)

= 0.002 g /litre

Hence normality = 0.002 g/litre

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