no.of molecules present in 1.8 gram of glucose
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Answered by
1
Answer:
Explanation:
Formula of Glucose = C6H12O6
Weight = 1.8 g
Molecular mass = 12*6 + 1*12 + 16*6 = 180
Number of atoms = 1.8/180 * 6.023 * 10^23 * 24
= 1.45 * 10^23
Answered by
0
Answer:
24 molecules are present in 1.8 g of glucose
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