No of molecules present in 5.6 litres of methane ( CH4 ) is ????
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✌️✌️ hey frnds.......
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1 mole of a gas occupies 22.4L at STP.
5.6L x 1mol/22.4L = 0.25mol...
I hope it's helpful ☺️☺️✅
____________________________________⬇️⬇️⬇️⬇️
1 mole of a gas occupies 22.4L at STP.
5.6L x 1mol/22.4L = 0.25mol...
I hope it's helpful ☺️☺️✅
alan35:
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Answered by
4
heyy matee .. here is ur ans .. no. of moles of methane = 5.6/22.4
no. of molecules =no. of moles ×NA that is avogadro's no. (6.022×10^22)
.
..
... i hope it helpss
no. of molecules =no. of moles ×NA that is avogadro's no. (6.022×10^22)
.
..
... i hope it helpss
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