No.of moles of carbonic acid in31 g
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0.01612258842353 no.of moles in 31g of carbonic scid
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Heya Friend !!
Formula of Carbonic Acid is H2CO3
Given mass = 31 g
Molecular mass of H2CO3 = 2 × (molar mass of H) + (molar mass of carbon) + 3 × (molar mass of oxygen)
= (2×1) + 12 + (3×16)
= 2 + 12 + 48
= 62 g / mol
number of moles = ?
We know that number of moles = Given mass (m) / molecular mass (M)
n = m / M
n = 31 / 62
n = 1 / 2
n = 0.5 moles
Hence , the number of moles of carbonic acid in 31 g is 0.5 .
Formula of Carbonic Acid is H2CO3
Given mass = 31 g
Molecular mass of H2CO3 = 2 × (molar mass of H) + (molar mass of carbon) + 3 × (molar mass of oxygen)
= (2×1) + 12 + (3×16)
= 2 + 12 + 48
= 62 g / mol
number of moles = ?
We know that number of moles = Given mass (m) / molecular mass (M)
n = m / M
n = 31 / 62
n = 1 / 2
n = 0.5 moles
Hence , the number of moles of carbonic acid in 31 g is 0.5 .
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