Question

No of moles of nitrogen in 56 g and no of atoms and no of atoms in 56 g

Answer 1

we know that { mole= weight/molecular weight}

mole of Nitrogen = 56(weight)/14(molar mass)
mole of Nitrogen =4moles

1Mole has 6.023×10^23atoms (Avogadro number)
no . of atoms =mole ×avogadronumber
no.ofatoms in 4 mole Nitrogen =4×6.023×10^23

so your answer is= 24.092×10^23atoms

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