Question

no of moles of O2 in 10.6 g of NaCO3​

Answer 1

Answer:

0.3 mol or 4.8g

Explanation:

The molar mass of Na2CO3 is 106 g

10.6g is 10.6/106 = 0.1mol.

Therefore, there are 0.1 “mol” of 3 O.

So, we have 3 x 0.1mol = 0.3mol of oxygen atoms, or 0.3 x 16 = 4.8g of oxygen.

Answer 2

Answer:

There are 0.15 mole of oxygen in 10.6 g of sodium carbonate.(NACO3)

Explanation:

molar mass of sodium carbonate (NACO3) is 106 g/mol.

So 1 mole (106g) of NA2CO3 contains 3 atoms of oxygen.

which is equivalent to 1.5 mole of oxygen.

10.6g of  NA2CO3 will contain (10.6 x 1.5) / 106

15.9/106

= 0.15 mole

Therefore, there are 0.15 mole of oxygen in 10.6 g of sodium carbonate

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