Chemistry, asked by sree1207, 5 hours ago

no of moles present in 316g of potassium permanganate​

Answers

Answered by Daksh0404
0

Answer:

Approximately how many moles of potassium permanganate, KMnO4 , are present in 40 g of this compound? (Atomic weights: K = 39; Mn = 55; O = 16 )

Explanation:

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Answered by beulab2006
0

Answer:

1 moles

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Potassium Permanganate, or 158.033949 grams.

Explanation:

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