Question

No of molicules present in 1.12×10 to the power -7 CC of a gas at step is

Answer 1

Answer:

Correct option is

B

3.01×10  

12

 

given volume of gas =1.12×10  

−7

CC

6.023×10  

23

 molecules of any gas occupied 22400ml at STP

So,

1.12×10  

−7

CC volume occupied by  

=6.023×10  

23

×  

22400

1.12×10  

−7

 

​  

{1CC=1ml}

=3.01×10  

12

 molecules of gas

Explanation:

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