Question

no. of neutron in 3.6gm sample of NH4+

Answer 1

Answer:

given mass = 3.6 mg = 0.0036 g

(N = 14, H= 1)

molar mass = 14 +(1 x 4) = 14 + 4 = 18 g

No. of moles = 0.0036 / 18= 0.0002 moles of $NH_{4^{+} }$

No. of Electrons = 0.0002 x  [6 x $10^{23}$]

                         =12 x $10^{19}$electrons of NH4+

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Answer 2

Answer:

NH4+ 

given mass = 3.6 mg = 0.0036 g

(N = 14, H= 1)

molar mass = 14 +(1*4) = 14 + 4 = 18 g

No. of moles = 0.0036 / 18= 0.0002 moles of NH4+

No. of Electrons = 0.0002 * [6* 10^23]

                          =12* 10^19 electrons of NH4+

Explanation:

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