No of nucleosomes present in the nucleus of diploid eukaryotic cell which possess 3.3*10^9 bp. Give correct answers and I will brainlist....
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Answer:
A diploid human cell contains 6 × 109 base pairs. For every 200 base pairs, 1 nucleosome is present. Therefore the number of nucleosomes in a diploid cell is
(6x10^9)/200=3x10^7 nucleosomes.
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Given - Number of base pairs
Find - Number of nucleosomes
Solution - The number of nucleosomes is 16.5*10⁶.
The number of nucleosomes can be found using the unitary method.
200 base pairs coil up to form 1 nucleosome.
So, 3.3*10⁹ base pairs will form the number of nucleosomes = 3.3*10⁹/200
Number of nucleosomes = 16.5*10⁶
Thus, the number of nucleosomes present in the nucleus of the diploid eukaryotic cell which possesses 3.3*10^9 bp is 16.5*10⁶.
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