Question

No of odd days in 425 years
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Answer 1

Answer:

Find the number of odd days in 425 consecutive years. A period of 400 years consists of 0 odd days . In 25 years, there are 6 leap years and 19 ordinary years. Today is Thursday.

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Explanation:

Odd days left Day of the week

4 Thursday

5 Friday

6 Saturday

Explanation:

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Answer 2

No of odd days in 425 years is 5.

• A normal year consists of 52 weeks and 1 day.
• So the number of odd days in a normal year is 1.
• A leap year consists of 52 weeks and 2 days.
• So the number of odd days in a leap year is 2.
• There are 106 leap years in 425 years.
• Hence, the number of normal years is 319.
• Hence, the total number of odd days can be find by adding all the odd days.
• 319+(106*2)=319+212=531
• The number of days in a week is 7. Now divide 531 by 7
• 531/7
• The quotient is 75 and the remainder is 5.
• The number of odd days in a year is the remainder. Hence there are 5 odd days in 425 years.

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