Chemistry, asked by fuzailkhan1365, 5 days ago

no of oxygen atom presenr in So2 gas is equal to no. of oxygen atoms present in 4g so3 gas find mass and Vol of So2 gas​

Answers

Answered by shristiverma7575
1

Answer:

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Class 12

>>Chemistry

>>The p-Block Elements

>>Ozone

>>The number of oxygen atoms in 20 gm of s

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The number of oxygen atoms in 20 gm of sulphur tri-oxide SO

3

is the same as these present in x gms of Ozone. The atomic mass of sulphur and oxygen are 32 μ and 16 μ respectively. Find the value of μ. (12 gm)

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Solution

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Molar mass of the sulpheric trioxide is 32+2×16=80g/mol

Number of grams of O in 80g/mol in SO

3

=48g

Number of grams of O in 20g/mol in SO

3

=

80

48

×20

=12g

Number of moles in 12 oxygen=

16

12

=0.75

No of atoms in 0.75 moles of oxygen is

0.75×6.0×10

23

=4.515×10

23

Now, The molar mass of the Ozone is O

3

=3×16=48g

Since 6.02×10

23

atoms make 48g Ozone 4.515×10

23

atoms make

=

6.022×10

23

48

×4.515×10

23

=36g of Ozone

Answered by siddharthbhasal15
0

the same as these present in x gms of Ozone. The atomic mass of sulphur and oxygen are 32 μ and 16 μ respectively. Find the value of μ. (12 gm)

Medium

Solution

Molar mass of the sulpheric trioxide is 32+2×16=80g/mol

=36g of Ozone

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