Question

no of oxygen atoms present in 9.2 moles of sodium carbonate is ​

Answer 1

Answer:

1 mole of Na

2

CO

3

.10H

2

O contains 13 atoms of oxygen.

0.20 mole will contain 0.20×13=2.26

Hence, no of oxygen atoms = 2.26×N

A

=15.66×10

23

is the answer.

Answer 2

Explanation:

15.66 ×10

15 is the answer