Physics, asked by mygrand2wite, 10 months ago

No. of photon emitted every second 60W bulb will be ​

Answers

Answered by divyamyindia271
1

Answer:

p =  \frac{nh}{tw}

w=wavelength

60 =   \frac{n \times 6.6 {10}^{ - 34} }{w}  \\ n = \frac{60w}{6.6 \times  {10}^{ - 34} }

hope it helps

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