Question

no. of quadratic polynomial having -2 amd -5 as their two zeroes are no​

Answer 1

Answer:

Infinite many solution

Hope it will help

Step-by-step explanation:

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Answer 2

Answer:

Infinite

Step-by-step explanation:

Of u want one eq see below

Let

$\alpha = - 2 \\ \beta = - 5$

So,

$\alpha + \beta \\ = - 2 + ( -5) \\ = - 2 - 5 \\ = - 7$

$\alpha \beta \\ = ( - 2)( - 5) \\ = 10$

Now, putting these values in

$k( {x}^{2} - ( \alpha + \beta )x + ( \alpha \beta )) \\ = k( {x}^{2} - ( - 7)x + 10) \\ = k( {x}^{2} + 7x + 10) \\ let \: k \: = 1 \\ = {x}^{2} + 7x + 10$

Hence, the equation is x²+7x+10

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