Question

No. Of roots of 3x^2+4

Answer 1

Answer:

$x = i\sqrt{4/3}$   $x = -i\sqrt{4/3}$   where $i = \sqrt{-1}$

Step-by-step explanation:

$3x^2 + 4 = 0\\3x^2 = -4\\x^2 = -4/3\\x =+ \sqrt{-4/3} , \\ x = -\sqrt{-4/3} \\or\\x = i\sqrt{4/3} \\x = -i\sqrt{4/3} \\where\\i = \sqrt{-1}$

Answer 2

Answer:

0 roots

Step-by-step explanation:

3x^2+0x+4

by quadratic formula,

x = -b +/- root of b^2-4ac/2a  

x= -0+/- root of 0^2 - 4*3*4/2*3

since the quantity inside the root becomes negative , therefore the quadratic equation will have no real roots.