No. of unit celle present in I gram of Nach
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Answer:
hey mate your answer my dear friend i hope its help you
Step-by-step explanation:
mole of NaCl = 58.5 g = 6.02 ×10^23 formula units.
No. of formula units in 1 g of NaCl = 6.02×10^23/58.5
As one unit cell of NaCl contains 4 NaCl formula units, therefore, number of unit cells present in 1 g of NaCl = 6.02×10^23 /58.5×4=2.57×10^21
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Answer:
complete ans.
Step-by-step explanation:
Therefore, *1gram of Nacl* = 6.02358.5× 1028 molecules = 1.02 × 1022 molecules of *sodium chloride* = 1.02 × 10224 = 2.57 × 1021
*unit cells of sodium chloride*
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