Question

No. of zeros at the end of (45!)

Answer 1

Answer:

The number of trailing zeros in 45 Is 10.

Answer 2

Answer:

45/5=9    

9/5=1

then the no of zeroes =9+1=10

see 5*2=10 so we know that there would be more 2s than 5s so we simply did the division with least occuring

also if u have to find any no of prime nos in any factorial then u will do like this only , e,g., if u have to find no of 3s in 28!  then u will do it like this

28/3=9;

9/3=3

3/3=1

then no of 3s= 9+3+1=13;

Step-by-step explanation: