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Abc and bde are 2 eqi tri ; d is midpoint of bc. Find ratio of ar of abc and bde also fig.
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ar(triangle bde)=root under 3/4(bc/2)^2
=1/4(root3/4bc^2)
ar(triangle ABC)=root3/4bc^2
ar(triangle Abc)/ar(triangle bde)=root 3/4 bc^2×4/root 3/4bc^2
4/1
ar(triangle abc): ar(triangle bde)= 4:1
=1/4(root3/4bc^2)
ar(triangle ABC)=root3/4bc^2
ar(triangle Abc)/ar(triangle bde)=root 3/4 bc^2×4/root 3/4bc^2
4/1
ar(triangle abc): ar(triangle bde)= 4:1
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MYNAME098:
Nice ans sis..
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AND now tu to apne baat se mukar raha h
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