Question

No one has answered this please help this is my second timedoing this

Answer 1

Answer:

a. possible ways= 10 (numbers 0 to 9)

probability of getting correct one from first attempt= 1/10

b. with 2 wheels possible ways = 10*10= 100

probability of getting correct combination = 1/10* 1/10= 1/100

c. with 3 wheels possible ways = 10*10*10= 1000

probability of getting correct combination = 1/10* 1/10*1/10=1/1000

Answer 2

Answer:

a.

probability of opening lock in one attempt=1/10

b.

i)Number of possible combinations

0-0,1,2,3-----9 =10

1-0,1,2--------9 =10

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9-0,1,2,------9 =10

Number of possible combinations=10×10=100

ii)probability of opening lock in one attempt=1/100

c.

i)Number of possible combinations

0-1-0,1,2------9

-2-0,1,2-----9

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-9-0,1,2,3----9 = 100

Similarly for 10 numbers= 100×10 =1000

Number of possible combinations=1000

ii))probability of opening lock in one attempt=1/1000