Question

no reacts with O2 to form an nO2 when 10 gram of an O2 is formed during the reaction the mass of O2 consumed is

Answer 1

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Answer 2

3.52 gram of oxygen is consumed.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles of} NO_2=\frac{10g}{46g/mol}=0.22moles$

$2NO+O_2\rightarrow 2NO_2$

According to stoichiometry:

2 moles of $NO_2$ are formed on consumption of= 1 mole of $O_2$

Thus 0.22 moles of $NO_2$ are formed on consumption of=$\frac{1}{2}\times 0.22=0.11$ mole of $O_2$

Mass of $O_2=moles\times {\text {Molar mass}}=0.11mol\times 32g/mol=3.52g$

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