Math, asked by garv1510, 1 year ago

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Answered by akhilvinayak03

Answer:

(i) 6/36

(ii) 5/6

(iii) 5/36

Step-by-step explanation:

(Imagine this situation like tossing 2 dice, the it will be easy to understand)

Both the customers can visit the shop on 6 days(i.e. from Monday to Saturday)

Since the chance of them visiting is equally likely,

the probability of one customer visiting the shop in one week = 1/6(Either on Monday or Tuesday or Wednesday...etc.)

similarly, the other one also has a probability of 1/6.

Then, total outcomes= 1/6 * 1/6

=>1/36

So, the events possible are (Monday,Monday ; Monday, Tuesday ; etc.)

[like (1,1);(1,2); etc. in the case of tossing two dice]

Now, same day events are (Monday,Monday);(Tuesday,Tuesday);etc.

So, probability = 6/36

Then, different days are all the other events, i.e. , 36-6=30

So, probability = 30/36 = 5/6

Consecutive cases are (Monday,Tuesday);(Tuesday,Wednesday),etc.

So, no. of events = 5

then, probability = 5/36

Pls mark BRAINLIEST if you like it.

garv1510: its writen 5/6 only

garv1510: see

garv1510: total outcome is 36

garv1510: ok

garv1510: they went on the same days for 6 times

garv1510: so all other possibilities will be for different days

garv1510: here from 36 possibility 6 are for same days

garv1510: so 36-6= 30 will be from different days

garv1510: p(they went on different days)= no. if time they went on different days / total outcome

garv1510: samaj me aya kya... magaj me aya kya

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