Math, asked by RosyJannath170607, 6 hours ago

No scam please
Draw a graph of the following equations and find the area of the triangle made by the graph by the coordinate axis
i) 4x-3y=12
ii) x/3+y/4=1
iii) x/2 +y/3=1
iv) 3x-5y=15
V)x/3+y/5=1
Graph is important
No scams please
Nd no point rase because if someone sees it they can't answer the question but kuch bhi likh ke chale jate hai

Answers

Answered by bharatpalsingh137
1

Step-by-step explanation:

You can solve it yourself, m bs logic bta rha

(Step 1): Sb equations m x = 0 put kro to y ki value mil jayegi

(Step 2): Sb equations m x = 1 rakho and again y ki value milegi

(Step 3) : Fir vaps sbme x = 2 rakho, y ki value mil jayegi and again x = 3 put kro, y ki value find kro

4 values of x and 4 values of y are sufficient for drawing a graph of the given equation.

Graph bnana aata hi hoga and in case if you don't know to horizontal line x-axis hota h and y-axis vertical

Put the value of x and y and make the points jisme x ki value put krne pr y ki value milti h, and join all the points

And that's how you can draw a graph of the given equation.

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