Question

no scamming
first correct answer will be marked brainliest
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Answer 1

Answer:

√32 is the answer

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Answer 2

Answer:

PA = PB = 4 cm ( Tangents from external point) ∠ PAB = 180° - 135° = 45° ( supplementary angles) ∠ ABP = ∠ PAB =45° (Opposite angles of equal sides) ∠ APB = 180° - 45° -45° = 90° So Δ ABP is a isosceles right angled triangle