Question

no scamp plz if u don't know plz don't tell answer ​

Answer 1

Answer:

Option(D)

Step-by-step explanation:

8sec^2∅ - 6sec∅ + 1 = 0

=> 8sec^2∅ - 2sec∅ - 4sec∅ + 1 = 0

=> 2sec∅(4sec∅ - 1) - (4sec∅ - 1) = 0

=> (2sec∅ - 1)(4sec∅ - 1) = 0

=> 2sec∅ = 1 and 4sec∅ = 1

=> sec∅ = 1/2 and sec∅ = 1/4

Range of sec∅ is (-∞,-1) ∪ (1,∞)

Hence, number of real roots = 0.

#MarkAsBrainliest

Answer 2

8sec^2-6sec +1=0

can we use quadratic formula

-b+-sqrt(b^2-4ac)/2a

-(-6)+-sqrt((6)^2-4(8)(1))/2*8

6+-sqrt(36-32)/16

(6+-2)/16

sec theta=4/8=1/2

after this

we know that sec theta doesn't exist 1/2 kind of value.but i can satisfy the infinity

then we take sec theta's reciprocal i.e cos theta =1/sec

cos=2

we know that cos theta does'nt exist 2

therefore the answer is no solution