Question

no scams please......​

Answer 1

Answer: Hey! Here's your answer.

Step-by-step explanation:

Given : Square ABCD and equilateral triangle EAB.

To prove: (i) Angle DAE = Angle CBE = 30°

(ii) Triangle ADE is congruent to Triangle BCE.

(i) As given in the figure, Square ABCD and Triangle EAB share the same base.

WKT, Angle DAB = 90° (All interior angles of a square measure 90°)

We also know that, Angle EAB = 60° ( since Triangle EAB is equilateral)

Therefore, Angle DAE = 90° - 60° = 30°

Similarly, Angle CBE = Angle CBA - Angle EBA = 90° - 60° = 30°

Hence, Angle DAE = Angle CBE = 30°

(ii) In Triangles ADE & BCE,

Angle DAE = Angle CBE (previously proven)

AD = BC (since all sides of a square are equal in length)

EA = EB (since EAB is an equilateral triangle)

Therefore, by SAS congruence criterion, Traingle ADE is congruent to Triangle BCE.

Hence, proven.

Hope this helps! Pls mark as brainliest