no silly answer plz
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Answered by
0
In triangle ABC & DCB
angle BAC = angle BDC = 90° ( given)
AC = BD ( given)
BC = BC ( common )
Hence,
triangle ABC = triangle DCB. ( by R.H.S)
Hope it helps!!!
angle BAC = angle BDC = 90° ( given)
AC = BD ( given)
BC = BC ( common )
Hence,
triangle ABC = triangle DCB. ( by R.H.S)
Hope it helps!!!
sangini2002:
Rhs is for similarity not for congruency
Answered by
1
In triangle ABC and triangle DCB
angle BAC=angle CDB (given)
AC=DB (given 90 degree)
BC = BC (common)
so, By HL(Hypotenuse leg) axiom triangle ABC and DCB are congruent to each other.
angle BAC=angle CDB (given)
AC=DB (given 90 degree)
BC = BC (common)
so, By HL(Hypotenuse leg) axiom triangle ABC and DCB are congruent to each other.
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