Question

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Answer 1

Answer:

The boiling point of a solution 56.46 °C.

Explanation:

Boiling point of acetone = T= 56.30 °C = 329.30 K

Boiling point of the solution with 0.456 g of camphor = Tb

per 100 g of acetone = 17.2 K g/mol

1000 g of acetone =1.72 K kg/mol

The boiling point of a solution 56.46 °C.

Answer 2

SOLUTION ☺️

Given,

Kb per 100 gm of acetone= 17.2°C

Therefore

Kb per 100gm of acetone = 1.72°C

We know,

=) ∆Tb= 100Kbw2/M2w1

substituting the values

=) 1000×1.72×0.456/152×31.4

=) 0.16

Therefore boiling point of SOLUTION

=) 56.30+0.16

=) 56.46 °C

HOPE it helps