NO SPAM.
10J of work of required to move a charge of-200C from point A toB.
DETERMINE which of the two points is at a higher potential
Answers
Answered by
4
Answer:
As we know V=W/Q
V=10 J/200 C
=0.05
therefore, the pd is 0.05V
moved from point A to B hence A is at higher potential
Answered by
1
Answer:
When the direction of the Electric field is from "A" to "B" , a negative Charge of -200C will experience a force in the direction "B" to "A". To move against this force from "A" to "B" an external force in the direction "A" to "B" has to be applied which results in a positive work of 10J while taking the charge from "A" to "B".
Work done = potential energy gained = charge x potential difference
Therefore,
10J = (Vb-Va) x -200C
Vb-Va = - 0.05V
Va = Vb+0.05 V
The potential at point A is higher than the potential at B
MARK AS BRAINLIEST... :)
Similar questions