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An object of mass 5 kg is moving with a velocity of 10 m/s a force is applied that in 20s, it attains a velocity of 25m/s . What is the force applied on the object?
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Answer:
F=ma
given, M=5kg a= (4=10m/s v=35m/s t=25 sec) =(v-4)/t=35-10)25=1
f=ma
f=5x1=5n bhaiya aapka answer Ho Gaya friendes
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