no spam ans...state the relationship between alpha nd beta
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4
Heya...^_^
If u need the relationship in terms of quadratic equation , then it's ----
Alpha + Beeta = - (coefficient of x ) / coefficient of x^2
Alpha × Beeta = constant / coefficient of x^2
If u need the relationship in terms of quadratic equation , then it's ----
Alpha + Beeta = - (coefficient of x ) / coefficient of x^2
Alpha × Beeta = constant / coefficient of x^2
lumbi:
dear its not coefficient of a
a itself is a coefficient in ax^2+bx+c=0
Yeah I know
its coefficient of x^2
That was by mistake
ok
a is itself a coefficient
thnx
Answered by
2
There are 3 configurations of transistors i.e Common base, common emitter and common collector , so accordingly they have their gain factor i.e. alpha (A) , beta(B) and gamma(Y) respectively.
The gain factor (A) of common base config. and gain factor (B) of common emitter are related as - A = B/B+1 or the reverse B = A/A-1.
So from the above 2 equation it is clear that Alpha (A) is always less than 1 (A<1) and Beta (B) is always greater than 1 (B>1).
The gain factor (A) of common base config. and gain factor (B) of common emitter are related as - A = B/B+1 or the reverse B = A/A-1.
So from the above 2 equation it is clear that Alpha (A) is always less than 1 (A<1) and Beta (B) is always greater than 1 (B>1).
thnx
w/c
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