Question

#NO SPAM

ANSWER IS 2.

PLZZ SOLVE THIS.

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Answer 1

I think that 2 is not the correct answer

I think that 2 is not the correct answer Bcoz mine is 11/4

Hope that my answer will help you

Thank you for question

#answerwithquality

#BAL

Answer 2

Answer: 2

Step-by-step explanation:

$\tt \sin(30^{\circ}) = \dfrac{1}{2}\ ,\ \sin(45^{\circ}) = \dfrac{1}{\sqrt{2}} \\ \\ \\ \cos(60^{\circ}) = \dfrac{1}{2}\ ,\ \cos(45^{\circ}) = \dfrac{1}{\sqrt{2}} \\ \\ Given\ equation: \\ \\ 4\big(\sin^4(30^{\circ})+\cos^4(60^{\circ})\big)-3\big(\cos^2(45^{\circ})-2\sin^2(45^{\circ})\big)\\ \\ substituting\ the\ values\ we\ get: \\ \\ \implies 4\Bigg(\Big(\dfrac{1}{2}\Big)^4+\Big(\dfrac{1}{2}\Big)^4\Bigg)-3\Bigg(\Big(\dfrac{1}{\sqrt{2}}\Big)^2-2\Big(\dfrac{1}{\sqrt{2}}\Big)^2\Bigg)$

$\tt \implies \dfrac{1}{2} - \Big(-\dfrac{3}{2}\Big) = \dfrac{4}{2} = 2$

Hope this helps.