Question

No spam answers for the attachment plz.....

Answer 1

mark this one also as brainliest please...... please please please

Answer 2

Solution :-

Let AB be the height of the tower and DE be the height of the observer. 

Then,

 In Δ ACD ,AC/DC

= tan 30°

⇒ x/√30

= tan 30°

= 1/√3 ⇒

x = 20 mAB

= 20 m + 1.7 m= 21.7 m

So, the height of the tower is 21.7 m

$<marquee> Hello how r u?</u></em></strong></p><p><strong><em><u>[tex] <marquee> Hello how r u?☺♥☺♥☺♥☺♥☺♥♥♥♥</u></em></strong></p><p><strong><em><u>[tex] <marquee> Hello how r u?☺♥☺♥☺♥☺♥☺♥♥♥♥$