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✔️class 12th question
✔️ physics ncert volume 1
✔️ chapter 3
note : Answer should be solved in copy
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a square coil of side 10cm consist of 20 turns carries a current of 12A. the coil is suspended vertically ajd normal to the plane of coil makes an angle 30° with direction of horizontal magnetic field of 0.80tesla. what is the magnitude of torque experienced by the coil.
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Your answer in the attachment given above ...... ⏫ ⏫ ⏫ ⏫ ⏫
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Answer:
answer is 0.96N
Explanation:
torque= INABsinα
= 12*20*0.1*0.1*0.8*0.5
=0.96
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