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Answer 1

Answer:

Angular momentum in Physics is defined as the moment of momentum.It is an axial vector involving cross product of the distance from the reference and the momentum of the body .

Mathematically:

Let angular momentum be denoted as L vector.

So, L = r × (mv)

Keep in mind that distance vector is placed first in the cross product.

In algebraic terms we can also say that

angular momentum = (mv) × ( r⊥)

(r ⊥ ) refers to the perpendicular distance of the body from the reference line.

Calculation:

Now as the body is moving parallel to the x -axis, we have to take the perpendicular distance from x -axis ,i.e "b"

[ r ⊥ = b ]

Now putting values on the algebraic formula:

L = (mv) × r⊥

L = (mv) × b

L = mvb.

SO THE ANSWER IS OPTION 1) mvb

Answer 2

${\huge{\tt AnsweR}}$

Option ( A )

${\huge{\tt ExplanatioN}}$

The given question is that a paryicle of mass m is moving with the constant velocity ( v = velocity ) , parallel to the x - axis as how show in the image in the question.

It's angular momentum is about orgin = 0

${\huge{\tt NoteS}}$

1. Let the angular momentum be L.
2. Let velocity be V.
3. The angular momentum is equal to ( MV ) × ( R ⊥ ) or M × R × ( MV ).
4. This symbol ( ⊥ ) refers the perpendicular distance of the body to the reference line.

Doing calculation to verify or check the answer.

= r ⊥ = b

Now adding the values , we get

L = ( MV ) × r ⊥

L = ( MV ) × b

L = MVB

Therefore , the answer is option ( A )