Question

No spam !!

Correct answers accepted!!

Explanation required!!

Wrong answers will be deleted on the spot!!​

Answer 1

$\huge{\pink{\red{\sf \boxed{Answer}}}}$

Correct option (2)

CrO2Cl2 , MnO4-

$\huge{\underline {\underline {\mathfrak{</strong><strong>Explana</strong><strong>tion</strong><strong>}}}}$

Metals taking higher oxidation states in a reaction are :

Chromium (Cr) and Manganese (Mn) .

$<font color = "red"><marquee>❤❤❤ Shukriya</p><p>❤❤❤</marquee> </font>$

Answer 2

Answer:

The correct answer is Option => 2.

$\bf \implies CrO_2\;Cl_2 , MnO_4^-$

Explanation:

According to the question,

We have to find which metal has the highes oxidation state.

Let us know -

• What is oxidation number ?

The oxidation number of an atom is the charge it appears to have when you count the electrons according to some arbitrary rules.

★ Points to remember :

• The oxidation number of a free element is always 0.
• The oxidation number of O in compounds is usually -2, but it is -1 in peroxide.
• The oxidation number of a monatomic ion equals the charge of the ion.

$\rule{300}{1.5}$

So, Let's Start by checking their charges/oxidation numbers of the various metals in the following options.

★ Option - 1 :

$\bf \implies [Fe(CN)_6]^{3-}, [Co(CN)_6]^3^-$

In option 1 we have the oxidation number -

$\implies \sf Fe = +3\quad, \quad Co+3$

$\rule{300}{1.5}$

★ Option - 2 :

$\bf \implies Cr-O2Cl_2,MnO_4^-$

In option 2 we have the oxidation number -

$\sf \implies Cr = +6\quad, \quad Mn+7$

$\rule{300}{1.5}$

★ Option - 3 :

$\bf \implies TiO_3, MnO_2$

In option 3 we have the oxidation number -

$\sf \implies Ti =+\;6\quad, \quad Mn+4$

★ Option - 4 :

$\bf \implies \bigg[Co(CN)_6\bigg]^{3-} , MnO_3$

In option 4 we have the oxidation number -

$\sf \implies Co = +3\quad, \quad Mn + 6$

$\rule{300}{1.5}$

Now, you can easily find the highest oxidation number state.

$\sf \implies Cr = +6\quad, \quad Mn+7$

$\bigstar\;\textsf{Oxidation number Mn in} \sf \bigg[MnO4\bigg]^-\;is\;\;\boxed{\bf 7}\quad and\;Cr in CrO_2Cl_2\;\boxed{\bf +6}}}}$

So, yes, The Option => 2 is the correct answer.