Question

No spam !!

correct answers accepted!!

wrong answers will be deleted!!

​

Answer 1

Hello My Friend,

Hope you are doing great!!

Here is your answer

Please select as Brainliest if helped✌️

#Hope It Helps you the best!

Cheers♥️

Answer 2

Answer:

Please be careful while differentiating the position function.

Given: Position varies with time as per the equation

x = 4/t - t^3 + 3t^4

To find : Velocity of the object after t = 1 sec.

Calculation:

[If x = f(t), then

velocity v = d {f(t)}/dt ]

x = 4/t - t^3 + 3t^4

=> dx/dt = v = -4/(t^2) - 3t^2 + 12t^3

Now putting t= 1

=> v = -4 - 3+ 12

=> v = 5 m/s.