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A,B,C are three points on OX, OY ,OZ respectively at distances a, b, c (a not equal to zero, b not equal to zero, c not equal to zero) from the origin O .Find the point from co-ordinates of the point which is equidistant from A, B, C and O
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QUESTION
A,B,C are three points on OX, OY ,OZ respectively at distances a, b, c (a not equal to zero, b not equal to zero, c not equal to zero) from the origin O .Find the point from co-ordinates of the point which is equidistant from A, B, C and O.
ANSWER
Correct Answer is -
- ( 2a , 2b 2c )
- Let P be the required point (x,y,z) and the point
- A,B,C and O are (a,0,0),(0,b,0),(0,0,c) and (0,0,0) ;
- We are given that PO=PA=PB=PC.
- Taking PO=PA or PO
- 2
- =PA 2
- , we get
- x 2 +y 2 +z
- 2 =(x−a)
- 2 +y 2 +z 2
- 0=a 2
- −2ax
- i.e.
- x= 2a
- Similarly taking PO
- 2 =PB
- 2 and PO
- 2 =PC 2
- , we get
- y= 2b and
- z= 2c
THANK YOU
Answered by
3
Let P be the required point (x,y,z)
and the point
A,B,C and O are (a,0,0),(0,b,0),(0,0,c) and (0,0,0) ;
We are given that PO=PA=PB=PC.
____________________________
Taking PO=PA or PO^2=PA^2,
we get
x^2+y^2+z^2=(x−a)^2+y^2+z^2
0=a^2−ax^2 x=a^2
____________________________
Similarly taking PO2=PB2 and PO2=PC2, we get
y=b^2 and z=c^2
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