History, asked by Anonymous, 1 year ago

❌❌NO SPAM❌❌

❌❌NO COPIED ANSWER❌❌

❌❌NEED DETAILED ANSWER❌❌​

Attachments:

Answers

Answered by Anonymous
2

✔✔Here is your answer in the attachment ✔✔

Attachments:
Answered by Anonymous
4

If we know the partial pressures for each component at equilibrium, where the partial pressure of \text A(g)A(g)A, left parenthesis, g, right parenthesis is abbreviated as \text P_\text AP

A

P, start subscript, A, end subscript, then the expression for K_\text pK

p

K, start subscript, p, end subscript for this reaction is

K_\text p =\dfrac{(\text P_{\text C})^c (\text P_{\text D})^d}{(\text P_{\text A})^a (\text P_{\text B})^b}.


Anonymous: tab as am going am going
Anonymous: so go na
sachinsingh62: hiii
sachinsingh62: @Tanya
sachinsingh62: good morning
sachinsingh62: r u busy
sachinsingh62: hii
sachinsingh62: hllo
sachinsingh62: good evening
Similar questions