Question

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Answer 1

✔✔Here is your answer in the attachment ✔✔

Answer 2

a) For this problem, we can use Gay-Lussac's Law of Combining Volumes:

If pressure and temperature are constant, the ratio between the volumes of the reactant gases and the products can be expressed in simple whole numbers.

Methane is represented by CH4 and a=have moleccular mass of 22.4

when methane is burned following reaction takes place 

CH4 + 2O2:::::>  CO2 + 2H20 '

In this reaction one mole of methane needs two moles of oxygen to be completely burned 

for 0.25 moles we can calculate as;

=0.25*22.4*2

=11.2 Liters 

Hope helps