Question

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Answer 1

✔✔Here is your answer in the attachment ✔✔

Answer 2

Explanation:

Given, mass of place of aluminium, m=1kg;

density of aluminium, ρ

s

=2700kg/m

3

;

density of water, ρ

w

=1000kgm

−3

As shown in figure, we have to find tension in the string in each case.

(a) When the aluminium piece is suspended in air

Tension, T=mg [Ref fig. (a)]

or T=1×10=10N

(b) When the aluminium piece is completely immersed in water,

mg=T+F

B

[Ref fig.(b)]

Where, F

B

= buoyant force acting on aluminium

T= tension in the string

∴T=mg−F

B

′

=1×10(1−

2700

1000

)

=6.296N.