Question

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Answer 1

Answer:

Given:-

The perimeter of a square is 64 m. The area of a rectangle is 6 m sq less than the area of the given square . If the breadth of rectangle is 10 m. Than find its length.

To Find:-

The length of the rectangle.

Note:-

☆ For finding length of the rectangle, we need to have its area as shown in the figure, so area of rectangle ~

6m sq less than area of square.

☆ If we want to the area of square, we need to have its side measurement

☆ For finding Side ( as per perimeter is given )~

Side = Perimeter/ 4

Solution:-

Perimeter of square is 64 m

Side = $64 m / 4$

Side = $16 m$

♧ So Now; for finding Area of square ,it is = Side × Side ( Side is 16 m)

Area of square = $16 m × 16 m$

Area of square = $256 m ²$

♧ Now; for finding Area of rectangle, it is = 6 m sq or (²) less than area of square ( Area is 256 m²)

Area of rectangle = $256 m ² - 6 m ²$

Area of rectangle = $250 m²$

♧ Now; for finding Length its formula is = Area of rectangle/ breadth

( area is 250 m², Breadth = 10 m)

Length = $250 m² / 10 m$

Answer:-

Length = $25 m$

Answer 2

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$perimeter \: of \: square = 64m \\ side \times 4 = 64 \\ side = 64 \div 4 = 16m \\ area \: of \: square = side \times side \\ = 256 {m}^{2}$

$according \: to \:the \: question \\ the \: area \: of \: rectangle \: is \: \\ 6m \: sq \: less \: than \: the \: \\ area \: of \: the \: given \: square \\ area \: of \: rectngle = 256 - 250 = \\ = 250 {m}^{2}$

$area \: of \: rectangle = l \times b \\ 250 {m}^{2} = l \times 10m \\ 250 = l \times 10 \\ l = 250 \div 10 \\ = 25m$

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