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GIVEN: Fx = 50 N ; θ = 30° ; Fy = ?
Fx = F Cosθ wherein θ = 30°
50 = F×√3/2
F = 50×2/√3
= 100/√3
= 57.73 N
Fy = F Sinθ
= 57.73×1/2
= 28.86 N.
Therefore, the magnitude of force = 57.73 N and the vertical component = 28.86 N.
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