Physics, asked by TheConqueror, 1 year ago

no spam please need urgently.

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TheConqueror: f=uRis friction=0.5*2*10=10N

TheConqueror: now F=30N

TheConqueror: net F=30-10=20N

TheConqueror: now acceleration=20/5 or different for both bodies i am confused here

TPS: You can do like this too. Here also, you will get acceleration as 4 m/s^2. Your method is also right. You are using acceleration=(net force)/total mass. But it might not work in all situations. It is better to draw FBD of all objects separately and analyse.

TPS: Velocity at the end of travelling 1m = √2as = √2×4×1 = 2√2 m/s

TPS: Deceleration = 5m/s^2

TPS: Work done = friction × distance

Answers

Answered by TPS

See the attachment. If you have any doubt, ask in the comments box.

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TheConqueror: s=0.8 m

TheConqueror: so total s= 1.8m for 2kg

TheConqueror: so finally friction=-18J

TheConqueror: ???

TPS: You got it!!!

TPS: Nice!:)

TheConqueror: Di is it right?

TheConqueror: :)

TheConqueror: thanx to u di

TheConqueror: aap konsi class me ho?

Answered by llItzTheLoveShotll

Refer to the above attachment

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