No Spam please
prove without using R.H.S.
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Proof:
In triangle PMO and PLO
PL=PM(given)
angle L = angle M =90
OP=OP
therefore PMO congruent to PLO(RHS criteria)
angle MOP = angle LOP(cpct)
thus OP is the bisector of angle AOB
In triangle PMO and PLO
PL=PM(given)
angle L = angle M =90
OP=OP
therefore PMO congruent to PLO(RHS criteria)
angle MOP = angle LOP(cpct)
thus OP is the bisector of angle AOB
ashk02:
im so sorry.. didn't notice that it said to solve without RHS.
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