Question

no spam please slove question (3)
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Answer 1

Step-by-step explanation:

in fig 1

since ac and ef are parallel

ade =dab

therefore dab=60

dbc and dba are linear pair so

dbc+dba=180

140+dba=180

dba=180-140=40

in a triangle sum of all angles is 180

so,dba+dab+bda=180

40+60+bda=180

bda=180-100=80

In fig 2

draw a line parallel to other two lines through angle y

now add 59 and 59

therefore y=59+59=118

in fig 3

50+3x+2x=180

50+5x=180

5x=130

x=26

now 3x=3(26)=78

2x=2(26)=52

now,2x+c=180

c=180-52=128

in fig 4

40+40+x=180

x=180-80=100

therefore x=100

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Answer 2

Answer:

in fig 1

since ac and ef are parallel

ade =dab

therefore dab=60

dbc and dba are linear pair so

dbc+dba=180

140+dba=180

dba=180-140=40

in a triangle sum of all angles is 180

so,dba+dab+bda=180

40+60+bda=180

bda=180-100=80

In fig 2

draw a line parallel to other two lines through angle y

now add 59 and 59

therefore y=59+59=118

in fig 3

50+3x+2x=180

50+5x=180

5x=130

x=26

now 3x=3(26)=78

2x=2(26)=52

now,2x+c=180

c=180-52=128

in fig 4

40+40+x=180

x=180-80=100

therefore x=100

Step-by-step explanation: